I can get minerr to work on (what I think is) your problem:
with:

You can define a matrix M with:

Which means that M is:

The rank of M is still 9, instead of 10, and its determinant is still 0 (according to the symbolic solver), so there is not a single, unique solution; this is still the same problem you had before.
Now you want to solve a in M*a=C, using minerr (that is, find a solution that is close).
Your guess values for vector a can be constructed with:

Your solve block might look like this:

And see, it produces an answer. But how good is it?
M multiplied with R1 should produce C. Let's see:

We can calculate the relative errors:

C9 and C10 are pretty closely obtained, but C2 is 7.5 % off.
Success!
Luc
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