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1-Visitor
March 10, 2015
Solved

Parabola problem

  • March 10, 2015
  • 1 reply
  • 4044 views

Hello,

I'm having a problem with defining parabola's function f(x) when a,b,c are unknown. I can solve a,b,c with given/find-procedure but I have no idea how could I make mathcad to give me the function included these now known a,b,c (something like: f(x) = 4x^2 +3x + 1)

I attached my work so far so maybe it's easier for you to understand what I meant above.

I would be very pleased if someone could help me out as soon as possible.

Sincerely,
Joni

(btw I'm using mathcad 15)

Best answer by AlanStevens

Have a look at the attached.

Alan

1 reply

23-Emerald V
March 10, 2015

Joni Sievola wrote:

Hello,

I'm having a problem with defining parabola's function f(x) when a,b,c are unknown. I can solve a,b,c with given/find-procedure but I have no idea how could I make mathcad to give me the function included these now known a,b,c (something like: f(x) = 4x^2 +3x + 1)

I attached my work so far so maybe it's easier for you to understand what I meant above.

I would be very pleased if someone could help me out as soon as possible.

Sincerely,
Joni

(btw I'm using mathcad 15)

You simply write the function down pretty much as you have it above!

f(x):=a*x^2+b*x+c

and that's that.

As you've used x as a variable already, if you want to plot it in 2D, then you'll have to plot it against a different variable (doesn't matter what as long as it's not x, y, a, b or c.

Stuart

collab - 15 03 10 Mathcad_parabola 01.JPG

jsievola1-VisitorAuthor
1-Visitor
March 11, 2015

Thanks for fast response mate!

But I'm still wondering what is the command for solving the function itself. I need the program to form me the function ( f(x)=something ) using now known a,b,c values.

It should give me it example in this way: f(x) = 4x^2 + 2x + 3

I hope you understand what I meant since english isn't my native lanquage:)

19-Tanzanite
March 11, 2015

Do you mean something like this:

function.PNG

Alan