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ttokoro
21-Topaz I
21-Topaz I
February 26, 2024
Solved

Puzzle-35. Find the Length DE. ABCD is rectangular. 5 areas are same sizes. AB=13 cm.

  • February 26, 2024
  • 2 replies
  • 2659 views

Not a question of mathcad but Mathcad can solve this.

Find the Length DE.

ABCD is rectangular. 5 areas are same sizes. AB=13 cm.

 

ttokoro_6-1708949375898.png

 

Best answer by terryhendicott

Hi

See Enclosed

2 replies

25-Diamond I
February 26, 2024

Its not difficult to get DE=6, but Mathcad or Prime were of no help here (or rather: weren't needed).

21-Topaz II
February 26, 2024
25-Diamond I
February 26, 2024

To be on the safe side we would need a symbolical solution, but trying to evaluate  the solve block symbolically fails.

Reason is that yD actually is irrelevant and yD could be set to any constant value and need not to be solved for.

So when we solve for four unknowns, we also only need four equations - one of the area equations is redundant anyway - if four of the five trinagles have an area of 1/5 of the total area, I would be surprised if the fifth triangle would have another area.
Now symbolical evaluation works OK

Werner_E_1-1708959439581.png

 

 

23-Emerald I
March 2, 2024

Attached. prime 4 express

ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
March 2, 2024

Hights of triangle DEG and ECH are not same but areas are same.

image.png

t.t.