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mshaw-31-Visitor
1-Visitor
Oct 16, 2014 9:14 AM UTC
Solved

Simple (I think) query. Convert a function to a Vector...

Hi,

I'm sure this is real easy but I can't see the wood for the trees. Given a function which uses a range variable as it's parameter. How do I convert this to a Vector for use in the fft function?

Please see attached.

Thankyou,

Mike.

MikeArmstrongAnswer
1-Visitor
Oct 16, 2014 9:26 AM UTC

Have a look at the attached.

I have used a pre-defined function to turn your range variable into a vector and also reduced fs to 512.

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4 replies

MikeArmstrong1-VisitorAnswer
1-Visitor
Oct 16, 2014 9:26 AM UTC

Have a look at the attached.

I have used a pre-defined function to turn your range variable into a vector and also reduced fs to 512.

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mshaw-31-VisitorAuthor
1-Visitor
Oct 16, 2014 9:46 AM UTC

Brilliant thankyou.

I'm trying to implement a MATLAB FFT solution in MATHCAD. One quick question for anyone reading - using an fs value of 1000 I can run the FFT function within MATLAB but for MATHCAD I need to use either 512, 1024, etc. Why is this?

Thankyou.

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StuartBruff23-Emerald V
23-Emerald V
Oct 16, 2014 9:51 AM UTC

Mike Shaw wrote:

Brilliant thankyou.

I'm trying to implement a MATLAB FFT solution in MATHCAD. One quick question for anyone reading - using an fs value of 1000 I can run the FFT function within MATLAB but for MATHCAD I need to use either 512, 1024, etc. Why is this?

Thankyou.

Because the Mathcad functions fft (, ifft, FFT and IFFT) assume vectors of length 2^m.

Use the functions cfft (,icfft, CFFT or ICFFT) instead - they allow arrays of arbitrary size.

Stuart

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