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ttokoro
21-Topaz I
21-Topaz I
March 20, 2020
Solved

Solve diagonal resistance of resistor 3D mesh.

  • March 20, 2020
  • 10 replies
  • 22248 views

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Diagonal resistance of regular polyhedron. R(4)=1/2, R(6)=5/6. How about R(8), R(12) and R(20)?

Best answer by ttokoro

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10 replies

24-Ruby IV
March 20, 2020

Cube.png

21-Topaz II
March 22, 2020

Hi,

A simplification of the network topology allows you to easily apply Thevenin's theorem:

rete composta 2.jpg

ttokoro
21-Topaz I
ttokoro21-Topaz IAuthorAnswer
21-Topaz I
March 24, 2020

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t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
September 2, 2020

image.pngThe diagonal resistance of resistor 3D mesh is 5/6 ohm.

How about 1*2 3D Mesh?

image.png

Each branch resister is 1 ohm. 

t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
September 8, 2020

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t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
September 9, 2020

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i=2:    1*1*1

i=3:    1*1*2

i=4:    1*1*3....

t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
July 10, 2021

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t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
July 31, 2021

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t.t.
18-Opal
February 21, 2022

I don't know why every body went to town on this. You already gave the V and I  so R = 5/6 ohms.

 

But as an academic exercise - as others have given but more colourful pictures are here:

 

https://www.rfcafe.com/miscellany/factoids/resistor-cube-equivalent-resistance-kirts-cogitations-256.htm

 

ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
February 21, 2022

This is not solving 3D 1*1*1 grid resistor mesh only. Using Mathcad or other mathematical programs we can calculate more interesting resistor grid problems.

1/3+1/6+1/3 can not use if the grid is 1*1*2. I post many unique resistor grid problems here.  This time 60 node soccer ball resistor grid result is shown. Please try to solve it because I can not find any answer in WWW sites. Without using Math software, we can not solve such as R1-2 of resistor ball. 

 

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1*1*2                                                                                        1*1*1

t.t.
18-Opal
February 21, 2022
21-Topaz II
March 15, 2023

What do you think of my solution?  Maybe I took the wrong node as a reference point?

2RBridges 0.jpg2RBridges 1.jpg2RBridges 2.jpg2RBridges 3.jpg2RBridges 4.jpg2RBridges 5.jpg2RBridges 6.jpg2RBridges 7.jpg2RBridges 5.jpg2RBridges 9.jpg2RBridges 10.jpg

ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
March 15, 2023

I will check your circuit. Please upload your Mathcad worksheet. I use Prime 9 to solve it.

I view your post and I understand this is 3D cube circuit with 12 one ohms to find the equivalent resistance of diagonal nodes. Node method is used to solve the circuit. I think this is the best method to solve the resistance.

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t.t.
21-Topaz II
March 16, 2023

Hi,
Undoubtedly, I made some mistakes. As for the theory, I was inspired by some texts including: "Linesr and non linear circuits" by L. O. Chua, C. A. Desoer, E. S. Kuh, for the construction of the TABLEAU matrix. You can find my worksheet attached.
Greetings

ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
April 19, 2025

3.4.5 ohms cube.

Pyta-345.jpeg

1 ohm circuit by 1 ohms. Each 1 ohm has different current when apply 1A for 1 and 13 nodes. 

1ohmby1ohms_3D.jpeg

t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
December 20, 2025

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Diagonal resistances of n-D cubes. AI only knows 3D and 4D ones. 

t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
December 25, 2025

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t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
January 24, 2026

Source and Image Credits: Ellenberg, J., Libedinsky, N., Plaza, D., Simental, J., & Williamson, G. (2026). Bruhat intervals that are large hypercubes.

 

New hyper cube circuit 2026.

HyperCube20262.jpgHyperCube2026-2.jpg

t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
January 28, 2026

12-5x6.jpg

ttokoro_0-1769594411535.png

 

t.t.
ttokoro
21-Topaz I
ttokoro21-Topaz IAuthor
21-Topaz I
February 21, 2026

Diagonal resistance of Galileo's 12-20 cube cauldron at the Milan Olympics.

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t.t.