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M
mschyma1-Visitor
1-Visitor
September 15, 2016
Question

Solving an equation that depends upon itself

  • September 15, 2016
  • 7 replies
  • 2307 views

Hi,

i have got to solve an equation that depends upon itself. I have attached the mathcad file.

When i try to evaluat the solution at a certain value of t, i get the message that the evaluation leads to an infinite recursion.

Im thankful for every support.

Kind regards,

Markus

7 replies

L
LucMeekes23-Emerald IV
23-Emerald IV
September 15, 2016

That's a nasty implicit equation you have there.

If I remove all (t)'s I get:

But for t=0, notice that ig(t) and u(t) are zero, so you get L(0)as:

Hope this helps.

Luc

F
Fred_Kohlhepp23-Emerald I
23-Emerald I
September 15, 2016

L
LucMeekes23-Emerald IV
23-Emerald IV
September 15, 2016

That's a different best you're dealing with, Fred. Look at how you placed ig.

And also notice how it kept L on the rhs.

So it's still implicit and not 'solved'.

Luc

L
LucMeekes23-Emerald IV
23-Emerald IV
September 15, 2016

Now if you dress up the equation to something like:

Look at the scale, not much variation in L(t)

Does this come any near to what you expect(ed)?

Luc

F
Fred_Kohlhepp23-Emerald I
23-Emerald I
September 15, 2016

Sometimes a solve block is the short answer.

M
MJG1-Visitor
1-Visitor
September 15, 2016

What about a solve block?

M
mschyma1-VisitorAuthor
1-Visitor
September 16, 2016

Thank you very much, i was able to solve the problem with your help.

Kind regards,

Markus

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