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15-Moonstone
May 24, 2021
Solved

Symbolic evaluation

  • May 24, 2021
  • 2 replies
  • 2738 views

I do not use symbolic evaluation very often so I am sure I am doing something wrong.  The following expression should equal mu_0 . Why do I keep getting the same thing back? Do I need a different keyword (I tried several)  or a modifier? 

 

JohnRudnicki_0-1621874339675.png

 

Best answer by Werner_E

@JohnRudnicki wrote:

The following expression should equal mu_0 .

No! Why do you think so? Its NOT equal to mu_0, just close for large values of mu_0.

The expression you show "approaches" mu_0 for large mu_0, but is always a bit larger.

Consequently we have

Werner_E_1-1621876662237.png

 

or

Werner_E_0-1621876644716.png

 

For a:=3 we have

Werner_E_2-1621876724306.png

 

 

 

2 replies

Werner_E25-Diamond IAnswer
25-Diamond I
May 24, 2021

@JohnRudnicki wrote:

The following expression should equal mu_0 .

No! Why do you think so? Its NOT equal to mu_0, just close for large values of mu_0.

The expression you show "approaches" mu_0 for large mu_0, but is always a bit larger.

Consequently we have

Werner_E_1-1621876662237.png

 

or

Werner_E_0-1621876644716.png

 

For a:=3 we have

Werner_E_2-1621876724306.png

 

 

 

15-Moonstone
May 24, 2021

I was actually trying to delete the last post, but could not figure out how to do it quickly enough. But now I get...

JohnRudnicki_0-1621876230406.png

 

ut

23-Emerald IV
May 24, 2021

You cannot delete your post, you can only edit (and empty if you like) it for about a day after it was posted.

 

Luc

23-Emerald IV
May 24, 2021

It's generally a good idea to plot the function you are dealing with:

LucMeekes_0-1621876982723.png

I guess for a<<1, and mu0 postive, it wil be hard to tell the difference between f(a,mu0) and mu0...

LucMeekes_1-1621877082601.png

QED.

 

Success!
Luc