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1-Visitor
February 13, 2018
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Symbolic evaluation of a 4th order equation

  • February 13, 2018
  • 1 reply
  • 1922 views

I tried to solve an equation symbolically. I dont know why it doesnt work. The solution must be simple, same as the numerical one with one extra unknown. Can someone please take a look. I tried different methods.

Best answer by Werner_E

You may use the modifiers "float" and "simplify" to see, that the result sure isn't so simply like you think 😉

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1 reply

Werner_E25-Diamond IAnswer
25-Diamond I
February 14, 2018

You may use the modifiers "float" and "simplify" to see, that the result sure isn't so simply like you think 😉

Bild.png

24-Ruby III
February 15, 2018

You forgot to specify the number of decimal places for the symbolic operator "float, n".

25-Diamond I
February 15, 2018

@VladimirN wrote:

You forgot to specify the number of decimal places for the symbolic operator "float, n".


No, I did not forgot, I was lazy and used the default (which is 20, if you don't specify a number).

BTW, its not the number of decimal places but the number of significant digits.