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Werner_E
Werner_EAnswer
25-Diamond I
January 31, 2021

How about adding a scaling factor?

Werner_E_0-1612107782195.png

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14 replies

Werner_E
Werner_E25-Diamond IAnswer
25-Diamond I
January 31, 2021

How about adding a scaling factor?

Werner_E_0-1612107782195.png

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    ValeryOchkov24-Ruby IVAuthor
    24-Ruby IV
    January 31, 2021

    New math constant?

    a/c=1.4142...

    c/a=0.70711...

     

     

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    Werner_E
    Werner_E25-Diamond I
    25-Diamond I
    January 31, 2021
    @ValeryOchkov wrote:

    New math constant?

    a/c=1.4142...

    c/a=0.70711...

     

     

    No, not new. Just sqrt(2) 🙂

    y''(0)=0 is equivalent with a = c* sqrt(2)

    You could use this right from the start in your equation.

     

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    Werner_E
    Werner_E25-Diamond I
    25-Diamond I
    January 31, 2021

    Sorry, the addition of the scaling factor was rather nonsense. Scaling the parameters a and c do the same job, so f is not necessary at all. I guess that getting rid of your variable x1 did the job.

    So a shorter solution is this:

    Werner_E_1-1612115835491.png

     

     

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    Werner_E
    Werner_E25-Diamond I
    25-Diamond I
    January 31, 2021

    And here is an even shorter approach which uses, that for the curve you are looking for we have a=c*sqrt(2)

    Werner_E_0-1612118960596.png

     

     

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    Werner_E
    Werner_E25-Diamond I
    25-Diamond I
    January 31, 2021

    This seems to be so far the shortest solution.

    Using no symbolic and no solve block

    Werner_E_0-1612122913337.png

     

     

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