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LucMeekesAnswer
23-Emerald IV
March 12, 2020

Create a 2 element vector and put in the equations. It's simple.

 

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Luc

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Fred_Kohlhepp23-Emerald I
23-Emerald I
March 11, 2020

Well, first you must assume that c3 is constant. . . 

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LucMeekes23-Emerald IV
23-Emerald IV
March 11, 2020

I think that Prime cannot solve a solve block symbolically.

But if you write it simply like this:

LucMeekes_0-1583930741370.png

You get your answer, for c1 and c2 in terms of the other items in the equations.

Note that u3 is common to both equations, so your problem can also be described with:

LucMeekes_0-1583930960385.png

This gives you a free choice for c1, then with u1, u2, c3 and l known, you can calculate c2.

 

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Luc

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    Werner_E
    Werner_E25-Diamond I
    25-Diamond I
    March 11, 2020
    @LucMeekes wrote:

    I think that Prime cannot solve a solve block symbolically.

     

    That's correct. It would be possible to do so in real Mathcad (=Mathcad 15 and below) but they destroyed this possibility when they developed Prime. So the only way is to use the symbolic "solve" command as you had shown.

     

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    LucMeekes23-Emerald IV
    23-Emerald IV
    March 12, 2020

    There's more wrong with your sheet.

    You define two equations with c1, c2, u1, u2 etc. these symbols are all labelled as constants.

    Then you write the Find function where you want to solve c1 and c2, but these are labeled as <nothing>.

    NOTE that a constant c1 is very different from a variable c1, or a unit c1 (if that would be defined).

    Written like this, Prime can never solve it.

     

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    Luc

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