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19-Tanzanite
Apr 3, 2024 10:04 AM UTC
Question

Why the laplace transform of a derivative not work when I added a constant value to it?

Hi,

Why when I added a constant value a to a derivative I see that the laplace transform of a derivative did not work as expected? Am I doing wrong something? Or?
Prime 9 sheet attached..

Cornel_1-1712138564809.png

6 replies

Cornel19-TanzaniteAuthor
19-Tanzanite
Apr 3, 2024 10:13 AM UTC

Cornel_0-1712139156384.png

 

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23-Emerald V
Apr 3, 2024 12:27 PM UTC

It seems like the derivative of b(x) is sometimes not recognised as such.

Check the labels of your variable, especially the x'es. All your x'es should be of the same label.

 

Success!
Luc

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Cornel19-TanzaniteAuthor
19-Tanzanite
Apr 3, 2024 12:40 PM UTC

I checked x-es labels...they are the same:

Cornel_0-1712147901474.png

Cornel_1-1712147933831.png

Cornel_2-1712147952202.png

Cornel_3-1712148005686.png

 

 

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23-Emerald V
Apr 3, 2024 1:09 PM UTC

Still there is a different one. the (x) between brackets is a '(variable)', not a 'variable'.

 

If that doesn't help, file a bug report.

 

Success!
Luc

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