Skip to main content
19-Tanzanite
February 3, 2016

I can get Qe1 and Qe2 in terms of alpha, but there is then a 6'th order polynomial to solve to find alpha (for which there is no general symbolic solution)!

See attached.

Alan

1 reply

19-Tanzanite
February 3, 2016

I can get Qe1 and Qe2 in terms of alpha, but there is then a 6'th order polynomial to solve to find alpha (for which there is no general symbolic solution)!

See attached.

Alan

Translate