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KaelLizak16-Pearl
16-Pearl
September 18, 2012
Question

computation with ibpl-fields

  • September 18, 2012
  • 0 replies
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computation with ibpl-fields (migrated thread) Posted: Jan 24, 2012 7:01 AM

   extern.jens-uwe.nixdorf     Posts: 68  Registered: Jan, 2010


Hi @all,

in a form we have an ibpl-picklist, where the users can select (multivalued) a number of items. In a second field we count the selected items with "relcount(<fieldname of ibpl-picklist>)". This is not a problem, but now i need another computation: the items in above mentioned picklist is not filtered by states, but i need the number of thise items in a special state. How can i do this?

Thanks and regards, Jens
Re: computation with ibpl-fields Posted: Jan 25, 2012 4:52 PM
Posted By:   Bradley.Johnston     Posts: 5 /  Registered: Feb, 2008  
This syntax should work for this purpose:
aggregate(<fieldname of IBPL-picklist>, Sum(State=="Desired State on Related Item"?1:0))

          

Re: computation with ibpl-fields Posted: Jan 26, 2012 2:39 AM
Posted By:   extern.jens-uwe.nixdorf     Posts: 68 /  Registered: Jan, 2010  
Aah, thanks, i'll try this. BTW: Whats the meaning of "?1:0" at the end of this line?

best regards, Jens

          

Re: computation with ibpl-fields Posted: Jan 26, 2012 2:55 AM
Posted By:   matthias.rump     Posts: 166 /  Registered: Mar, 2008  
It's a "if - then- else" clause (like in Java or C)

<logical condition> ? <action in case of true > : <action in case of false>

As a result, the expression
Sum(State=="Desired State on Related Item"?1:0)

counts every Item in the desired state with value 1 and all items in any other state with value 0.

See the computed fields expressions part of your user manual for details.

HTH Matthias

            

Re: computation with ibpl-fields Posted: Jan 26, 2012 2:59 AM
Posted By:   extern.jens-uwe.nixdorf     Posts: 68 /  Registered: Jan, 2010  
Oh, thanks. I think sometimes its usefull to know how coding works

regrads, Jens
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