Defining the layers

Forum|Forum|1 year ago
September 27, 2024
3 replies
7688 views

Last time we wrote this function to classify soil layers. I need to show that in the plot can that be possible in mathcad ?. I need to connect the table with the plot . so it draws horizontal marker whenever the layer changes. or change colors ..any kind of change to make it possible for the reader to understand it changes layer type

Like (y ) will be both z and ztop to draw the plot .

z is the depth

ztop the thickness of the layers

1_7A-plots.zip

2_7A.xlsx

Best answer by Werner_E

OK, upon rethinking I guess that two colors are all thats needed

W

Werner_E

25-Diamond I

Not sure but cold it be that you are looking for something like this

It would also be possible to color the various section according to their depth, but this would mean that we have to split both vectors i various subvectors and use them in the plot, which also means that you have a lot of entries (8) at both axis and would need to manually add or remove entries it the number of z.top values changes.

Prime 10 file attached

1_WE_20240927(1)_7A-plots.zip

W

Werner_E

Answer

25-Diamond I

OK, upon rethinking I guess that two colors are all thats needed

1_WE_20240927(3)_7A-plots.zip

Y

YA_10963798

Author

14-Alexandrite

Dear Werner,

Is it possible to merge these to programs together. I need to show the levels in the plot in the left , I couldn't do that because it shows error . instead of using only q12 I need to use The Qcza which contains all of the qcza...

I previously used z12 because it is the longest. So it is okay to use Qcza and z 12 not Z

I also have a mistake , I couldn't include the unit of the infinity

Unfortuantely, I couldn't open the sheet you sent because it is higher version than mine. I use prime 9

Thanks in advance

1_7A-&-7B-plots.zip

W

Werner_E

25-Diamond I

Better always state the version of Prime you are using.

I guess the errors you made were already corrected by Stuart.

You misinterpreted the 1x2 matrix with the units as a 1 x 4 matrix. I used the implicit unit multiplication (Ctrlk-Shif-U) and not an explicit multiplication sign between NaN and the units.

You missed the unit meter for the infinity "value".

But it still does not make much sense to use the full combined vector Q.cza as first argument and the vector z[12 as the second one, as only a small part of the plot would show.
You would have to use the combined vector Z as second argument, but probably my program would fail because it assumes the values in the second argument to be sorted by size. So it would be needed to change the function splitIn2 to cope with a vector z where sorted vectors are stacked and separated by NaN's.

Instead if doing so, I wrote a separate function splitAll which you can call with q.cza and z which loops through the vectors,uses the original splitIn2 function and stacks the 14 results one on top of the other: