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rireland-bowcot12-Amethyst
12-Amethyst
October 9, 2018
Solved

Call function based on visability of an image

  • October 9, 2018
  • 1 reply
  • 1735 views

I'd like to call the function below base on the visibility of an image but i am unaware of how to do this. Could someone help please? 

$scope.intro = function() {
	var labelText = $scope.view.wdg['checkstart'].text; 
	var spokenText = labelText.substr(labelText.indexOf(" ") + 1);
	$scope.app.speech.synthesizeSpeech({ 'text': spokenText });	
}

Thanks

Best answer by ClayHelberg

It depends on what you mean by "visability".

 

If you mean "when the visability parameter is set to true", then yes, you can do that using $scope.$watch, something like this:

$scope.$watch('view.wdg["image-1"].visible', function (val) {
 if (val) {
 $scope.intro();
 }
}

However, if you mean "when the user moves their device around so the image enters their field of view", then I think the answer is no. I don't think there's a way to detect whether an object is in the viewport or not. (I would be happy to be proven wrong, if there is a way to do this!) I also don't know of a way to get the location of the camera relative to the 3D view origin, so you can't try to derive it that way.

1 reply

C
ClayHelberg18-OpalAnswer
18-Opal
October 9, 2018

It depends on what you mean by "visability".

 

If you mean "when the visability parameter is set to true", then yes, you can do that using $scope.$watch, something like this:

$scope.$watch('view.wdg["image-1"].visible', function (val) {
 if (val) {
 $scope.intro();
 }
}

However, if you mean "when the user moves their device around so the image enters their field of view", then I think the answer is no. I don't think there's a way to detect whether an object is in the viewport or not. (I would be happy to be proven wrong, if there is a way to do this!) I also don't know of a way to get the location of the camera relative to the 3D view origin, so you can't try to derive it that way.

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