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SK_1363990610-Marble
10-Marble
January 29, 2026
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How to model different spring stiffness for loading and unloading in Creo Mechanism (MDO)

  • January 29, 2026
  • 2 replies
  • 365 views

In Creo Mechanism (MDO) motion simulation,
I would like to use different spring constants for the loading and unloading (return) directions, in order to represent spring hysteresis.

Is there any way to simulate this behavior in MDO?
If not directly supported, what is the recommended workaround?

Best answer by SweetPeasHub

MDO does not have nonlinear spring.

Also, relations are not linked/updated to measures during analysis. (limited usage)

 

The proper way is with a force/torque motor with the math necessary.

This is linear spring example. You should be able to apply similarly to torsion spring.

 

Setup measures: Lengthofspring(L), Velocityofspringjoint(VelX)

user defined measures:

FreeLength(FreeL) = 5.0 (just a number to capture the free length)

Sign = ((FreeL-L)*VelX)/abs(((FreeL-L)*VelX))

 

Make force/torque Motor with primary variable Sign.

Set domain for sign positive and one for negative.

Each with force based on spring length

(L-FreeL) * 30    Domain(-1.0 <= Sign < 0.0)

(L-FreeL) * 20   Domain(0.0 <= Sign <= 1.0)

 

Note: The signs of measures matter, check simulation and reverse Rate1 Rate2 if necessary.

If visualization of the spring is desired, place a very low stiffness spring, otherwise only the force motor applies the representation of the spring.

Also, as a pro tip, many things like friction, aerodynamic drag, etc. can be applied as equations within force motors.

 

SweetPeasHub_1-1770047244097.png

 

SweetPeasHub_2-1770047337767.png

 

 

 

 

2 replies

R
remy21-Topaz I
21-Topaz I
January 30, 2026

Hi 

just thinking out loud : did you try and use a parameter, relations and analysis ?

the stiffness could take a value depending on the direction.

the stiffness of the spring can be set a parameter

that parameter can be define by a relation

that relation could give different values to the stiffness 

now you need to find how to pick the direction 

maybe try with measures

my two scents



    S
    SK_1363990610-MarbleAuthor
    10-Marble
    February 2, 2026
    I didn’t realize relations could be used like that. Thank you

    I will try it like below. 

    If measure_ω > 0

    spring_k=30

     

    Else

    spring_k=20

    S
    SweetPeasHub17-PeridotAnswer
    17-Peridot
    February 2, 2026

    MDO does not have nonlinear spring.

    Also, relations are not linked/updated to measures during analysis. (limited usage)

     

    The proper way is with a force/torque motor with the math necessary.

    This is linear spring example. You should be able to apply similarly to torsion spring.

     

    Setup measures: Lengthofspring(L), Velocityofspringjoint(VelX)

    user defined measures:

    FreeLength(FreeL) = 5.0 (just a number to capture the free length)

    Sign = ((FreeL-L)*VelX)/abs(((FreeL-L)*VelX))

     

    Make force/torque Motor with primary variable Sign.

    Set domain for sign positive and one for negative.

    Each with force based on spring length

    (L-FreeL) * 30    Domain(-1.0 <= Sign < 0.0)

    (L-FreeL) * 20   Domain(0.0 <= Sign <= 1.0)

     

    Note: The signs of measures matter, check simulation and reverse Rate1 Rate2 if necessary.

    If visualization of the spring is desired, place a very low stiffness spring, otherwise only the force motor applies the representation of the spring.

    Also, as a pro tip, many things like friction, aerodynamic drag, etc. can be applied as equations within force motors.

     

    SweetPeasHub_1-1770047244097.png

     

    SweetPeasHub_2-1770047337767.png

     

     

     

     

      S
      SK_1363990610-MarbleAuthor
      10-Marble
      February 3, 2026

      relations are not linked/updated to measures during analysis.
      -> thank you for the information.

      Your solution looks like it work. I will try.
      Thank you

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