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15-Moonstone
April 16, 2018
Question

Simulation of a lifting CE

  • April 16, 2018
  • 1 reply
  • 15907 views

Hello,
To calculate a hoist as in the attached image, how do you define the crane attachment point at the top and the motor attachment point at the bottom.
In Simulate you can not leave two parts free.
Blocking for example the point of the crane will give a false representation of the deformation.
Cordially.
Denis.

 

1 reply

17-Peridot
April 16, 2018

Simulate can leave two parts free.  (some degrees of freedom (d.o.f.) free)

IF you have applied all loads from a Free Body Diagram (FBD) and determinate Static case.

This means you are in static equilibrium.

Then turn on inertia relief check box at static Analysis Definition. (this resolves any numerical rounding errors that make the part move and not be static)

Probably best load type is BEARING Load. for hoist pin and mass pin (motor)

 

Another way may be cut in half and use planar symmetry since the hoist rig appears symmetric from top to bottom.  Again inertia relief.

 

Another way instead of inertia relief for any case is to hold some area where stress is insignificant in the missing DOF.  If FBD and loads are accurate then the stress will not be very much.  There is a specific technique from PTC on constraining parts  in static equilibrium.  I could not find it in their knowledge base so it is attached here.

 

I found a related article at PTC support.

 Article - CS59477

 

And here is the static equilibrium technique.  It was redone for a thermal study but it is the same method.

Suggested Technique for Modeling Free Thermal Expansion

http://support.ptc.com/cs/cs_25/howto/mst728/mst728.htm#_ga=2.258133832.398535393.1523881733-1278185974.1478613588

 

15-Moonstone
April 17, 2018

Hello,
Thank you for these explanations.
I will try to apply them.
Cordially.
Denis

15-Moonstone
April 26, 2018

Hello,
Thank you for your model.
But in the case of my Cé, the fixation is in a circle, how can I put points there to fix the degrees of freedom as on your bridge?
Cordially.
Denis.

skunks
19-Tanzanite
May 8, 2018

ptc.JPG

17-Peridot
April 26, 2018

maybe this?

Lift2.JPG

 

skunks
19-Tanzanite
April 27, 2018

Hello Denis,

 

I recommend rigid links.

skunks
19-Tanzanite
April 27, 2018

Hello Denis,

 

better example test_d_new.zip

15-Moonstone
May 9, 2018

Good morning,
Oops, I had the explanation right in front of me.
But unfortunately I don't read English. (neither speaks nor writes it).
Thanks for the highlight.
Sincerely.
Denis.

 

https://www.deepl.com/translator

skunks
19-Tanzanite
April 27, 2018

Unable to play video. Please try again later.
(view in My Videos)

15-Moonstone
May 10, 2018

Good morning,
The principle of "spring" is still very obscure for me.
In your different examples it is placed in different places.
Can we find a document that explains the procedure to follow for using the "spring"?
Sincerely.
Denis

15-Moonstone
April 28, 2018

Hello,
I thank you for your very detailed explanations and your models.
On the other hand I did not understand the utility of the spring in the model test_d_new.
(Can not read the video)
Cordially.
Denis

skunks
19-Tanzanite
May 16, 2018

typical spring to ground

skunks
19-Tanzanite
April 30, 2018
17-Peridot
May 16, 2018

In this case use a spring because constraint on the weighted link dependent node is not allowed.

The general spring replicates the desired constraint because it has stiffness settings for all 6 d.o.f.

see image.

 

Some of the ways springs are used:

To constrain a model so it is a static case.  (eliminate d.o.f.)

To model some component stiffness as a simplification.

To model bearing/joint stiffness less than rigid.  (skunks example is held at a bearing area)

To stabilize the solving for a component held only by contact friction. (use a low stiffness spring)

 

The option inertia relief also constrains any free d.o.f.  And in the case of the unbalanced load mass of weight at the bottom joint vs mass of weight plus mass of lifting rig at the top joint, the inertia relief applies gravity to the model until the load is balanced and all d.o.f are held = static case.  That is why I did not have to include gravity in the unbalanced model because inertia relief is a type of gravity load.  Inertia relief is why no spring is needed for adding constraint on free d.o.f.

 

Inertia relief is a powerful tool because it allows the engineer to use a free body diagram with only loads applied and no constraints.  Of course the free body diagram must be force and moment balanced as usual but there are small numerical errors that the inertia relief can "fix".  In the case of any free body diagram with a gravity load, the gravity load is omitted when doing the FEA with inertia relief because the inertia relief will apply the gravity automatically to re-balance the forces.

 

 

ConstrainDepWeighted.JPG

 

 

 

skunks
19-Tanzanite
April 30, 2018

fig6.jpg

fig7.jpg

fig8.jpg

fig9.jpg

fig10.jpg

skunks
19-Tanzanite
May 16, 2018

it's not static model

modal_not_static.JPG

skunks
19-Tanzanite
April 30, 2018

fe_lifter.prt vs. fe_lifter_.prt

15-Moonstone
May 16, 2018

Hello Skunks, Sweetpeahub.
Great, I thank you for all these explanations and drawings as well as for the time spent on the subject.
I will study all this information.
Sincerely.
Denis