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Best answer by Werner_E

Actually you only have ONE ODE, not two!

Theoretically you could solve the second equation for T.g and replace that in the first one. So you are allowed for just one IC!

In your solve block h(t) it unknown, too, so you would have to solve for it, too or you have to eliminate it!

Werner_E_0-1602649207622.png

 

1 reply

W
Werner_E25-Diamond IAnswer
25-Diamond I
October 14, 2020

Actually you only have ONE ODE, not two!

Theoretically you could solve the second equation for T.g and replace that in the first one. So you are allowed for just one IC!

In your solve block h(t) it unknown, too, so you would have to solve for it, too or you have to eliminate it!

Werner_E_0-1602649207622.png

 

    M
    ML_94476061-VisitorAuthor
    1-Visitor
    October 14, 2020

    I did not realize I had h1 in the solve block still. I am losing it! When solving for Tg, how were you able to display the values? Using your method, I received "The symbolic result returned too large" error?

    W
    Werner_E25-Diamond I
    25-Diamond I
    October 14, 2020
    @ML_9447606 wrote:

    I did not realize I had h1 in the solve block still. I am losing it! When solving for Tg, how were you able to display the values? Using your method, I received "The symbolic result returned too large" error?

    Note that I did the symbolic solve AFTER variables like I or sigma were defined and that I replaced T.w(t) by the value you provided for T.w(0).

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