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1-Visitor
September 16, 2012
Question

Derivative of a vector-argument function

  • September 16, 2012
  • 3 replies
  • 3462 views

Hello!

Could you please help me as I am a newbie in the Mathcad world.
For a university homework, I was trying to solve some simple linear programming tasks (which I did).

However, something goes wrong when I am trying to find the partial derivative of a function which I define as R(y):= cT * y.

And 'c' is a 2D vector.

y is supposed to be from R^2, but I guess, MathCAD doesn't just get it and treats y as a scalar. Am I right? Is there a way to tell MathCAD that y is indeed a 2D vector?

My objective: I want to find d/dy_1 and d/dy_2 of R separately, or at least get a 2D vector containing these derivatives at a particular point.

What should I do? Is there a way to do it without redefining the function?

Please see the attached file for the details.

Thank you so much in advance!

Yours,
P.

3 replies

19-Tanzanite
September 17, 2012

Pavel Kabir wrote:

Is there a way to tell MathCAD that y is indeed a 2D vector?

My objective: I want to find d/dy_1 and d/dy_2 of R separately, or at least get a 2D vector containing these derivatives at a particular point.

What should I do? Is there a way to do it without redefining the function?

Do you really need Mathcad to do this for you? The partial derivatives with respect to y1 and y2 are just the two elements of c here, as R(y) = c1.y1+c2.y2

Alan

12-Amethyst
October 22, 2012

I don't use Prime yet, but it works okay in Mathcad 15 if the c vector is specified.Capture.JPG

24-Ruby III
October 22, 2012

It works fine in Mathcad Prime 2.0 too:

Pic_1.png

12-Amethyst
October 22, 2012

Here is another possible option that you can try,

Regards

Andy