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3-Newcomer
February 26, 2023
Solved

Generator Capability Curve

  • February 26, 2023
  • 5 replies
  • 4154 views

Can someone please explain how the right side (RHS) of the equation below represents active power (P)?

        

           

 Explain P: = PFUL*MVA + (MVA - PFUL*MVA) *i/N

 

given N = 2000, and

I run from zero to N.

 

 

 

 

Best answer by ppal_255687

There Are Two Types Of People in this world: those who can extrapolate incomplete data

 

ppal_0-1678395673366.jpeg

 

5 replies

23-Emerald I
February 27, 2023

Going to need more than that!

 

Is there a mathcad sheet with definitions of terms?

3-Newcomer
March 5, 2023

PFUL stands for Upper Power factor.

 

MVA stands MVA of the generator.

 

Thanks.

23-Emerald IV
March 5, 2023

If "MVA" is "MVA of the generator", then "MVA" is "MVA of the generator of the generator of the generator of the generator of the generator of the generator of the generator of the generator of the generator of the generator of the generator of the generator of the generator of the generator......"

In other words, a circular definition. That doesn't seem right.

So what is "MVA of the generator"?

 

Can you provide a source for the expression that you want to have explained?

 

Success!
Luc

3-Newcomer
March 6, 2023

Hello Fred, 

 

Thanks for the support. 

 

I am actually looking for someone to confirm the Active Power expression. 

 

My thinking was the first expression is the initial active power, the incremental values are calculated using the expression in the brackets. 

 

Thanks 

23-Emerald I
March 9, 2023

I'm not sure what you're looking for.  You typed an expression that would generate a vector in Mathcad (i/N where i is a range variable creates a vector) and I showed you how to plot it.  Your dialog with LucMeekes indicates you're looking into active and reactive power in AC circuits.

 

Power Factor depends on circuit parameters and frequency of the AC power.  Attached is a short discussion of power factors, phase angles and AC circuit components.  I'm not sure it addresses what you're looking for, but it may shed some light, and it was fun to build!  Prime 4 Express.

3-Newcomer
March 9, 2023

Hello Fred,

Thanks for the support.

My question was more of a programming issues than theory.

I was looking for the explanation of how the relation below gives real/active power :

Plag = MVA*PF + (MVA – MVA*PF)*(i/N) .

where PF is power factor

This is because as far as I can remember, P = S*PF, and (MVA – MVA*PF) is (MVA – P)*(i/N).

I cannot readily see how the term (MVA – P)*(i/N) adds to MVA* PF to give active/real power in the light of the expression S = P + jQ ,

Again, thanks much for all the support.

18-Opal
March 7, 2023

ppal_0-1678151243323.png

 

23-Emerald IV
March 7, 2023

Yes, but:

LucMeekes_0-1678214258029.png

and, suppose it's meant to sum over all i, then:

LucMeekes_1-1678214312017.png

 

Luc

25-Diamond I
March 9, 2023

As you can see the helpers here are wildly guessing about the meaning of the formula.

One suggests "i" to be the index of sum (which is not shown in your post), another suggests it may be the imaginary unit.

So it sure would help if you provide a source for the formula as Liuc already demanded, so we could see how it really should look like and what the exact meaning of the used variables should be. Where does the formula stem from? Can you provide a link or the like?

18-Opal
March 9, 2023

There Are Two Types Of People in this world: those who can extrapolate incomplete data

 

ppal_0-1678395673366.jpeg