Newbie question......I put in degree units and the thing breaks

Hi William,

You have raised an expression involving units to a power involving a range variable or a vector. As a result, there is no way to determine the dimensions of the result. If an expression is defined with units, you can raise it only to a fixed real power.

Hope this can help.

/K

If you define a range variable with units you need to include the second term. Try a:=0*deg,1*deg...45*deg

Whether the argument to sin(x) is default radian or °, the result is a number or a range of numbers, dimensionless numbers ... as well as x*sin(x). If you put units ° , you just have to scale it again vs the default radian, but still dimensionless numbers [a range of numbers], in other words a dimensionless scaling function. Assume you do that part right and get the desired function, you are left with A [unit of something] and q [unit of something]. Their product are now in the corresponding unit system of the measured or entered A, q. The coefficient C is dimensionless , therefore you only need to put units in A & q. What you don't say is what alpha represents [ orientation, elevation or else]. The fact that you are using or borrowing a trig function is immaterial, it could be a piece of polynomial or any suitable model having same alpha argument.

jmG