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1-Visitor
October 6, 2010
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Passband Intermodulation

  • October 6, 2010
  • 2 replies
  • 12477 views

I have read recently that 3rd order intermodulation terms will be be 3 times greater in bandwidth than the original bandwidth of either of the original two signals. I tried to verify that, but am having some difficulty. I was trying to use the Heaviside Unit Step functions, to create rectangular passbands. I would appreciate any help on this. Attached is a Mathcad 11 file.

Bill

Best answer by LouP

Take an example IMD term from the sinusoidal version: a1*a2*a2*cos[ (-2w2+w1)*t]. The generalization for rectangular spectra is to have a1 and a2 be (baseband) time functions rather than constants. They may have rectangular spectra or any shape.

Define the spectral bandwidth of a1(t) and a2(t) to be bw1 and bw2. Multiplying functions in time corresponds to convolution in freq. domain. Thus the sample term above has a bandwidth defined by the convolution [ a1(t) convolve a2(t) convolve a2(t) ]. The spectral bandwidths add when spectra are convolved. Therefore, this example term has a spectral bandwidth of bw1+2*bw2 centered at f = -2*f2+f1 . Each term in the expansion is treated similarly. Clearly, the maximum spectral width of the third order terms is 3*bw1 or 3*bw2 , whichever is larger.

The same principles apply to higher order IMD.

In the sheet, the attempt to create rectangular spectra is wrong. See comments in attached.

Lou

2 replies

19-Tanzanite
October 6, 2010

Don't you just need to put subscript f on variables p1 and p2 where they occur on the right-hand side of Kf?

Alan

BillDumke1-VisitorAuthor
1-Visitor
October 6, 2010

When I do that I get a "This value must be a vector".

Bill

19-Tanzanite
October 6, 2010

See attached. Since I don't know much about passbands it might not make physical sense! However, it works in Mathcad (M15) without any error messages.

Alan

BillDumke1-VisitorAuthor
1-Visitor
October 6, 2010

Thanks for the idea. I hadn't thought about opening it in Mathcad 15. No error messages, but the plot isn't right either. I will try spreading the frequencies out a little. Maybe they are too close together, for it to display properly.

Bill