A
Anonymous
February 1, 2010
Question
Solve block triangle question
- February 1, 2010
- 19 replies
- 10807 views
Hi Everyone,
Please see the enclosed MathCad worksheet & plot for an explanation of what I am trying to do.
I also enclose a PDF file with Figure 1 & Figure 2 to help explain as well.
Notes: -
#1 - Given the Fixed Hypotenuse ( =25.837) & Fixed Opposite (=8) I am trying to arrange a slope from top to bottom of the Opposite line marked in the centre of the red triangle in figure 1.
#2 - There are 3 'legs'/lines down which are HYP1, HYP2 & HYP3 which HYP1+ HYP2+ HYP3 = Hypotenuse = 25.83723
#3 - All the slopes of the legs / lines down are the same.
#4 - I have setup the current configuration for ease of explanation of what I am trying to do.
#5 - Note also that each HYP / leg meets the edge of the red triangle & the other HYP / leg start or finishes from that horizontal point.
#6 - The Combination of the vertical heights OPP1+OPP2+OPP3 = Opposite = 8
#7 - And lastly / obviously the ADJ1+ADJ2+ADJ3 = Adjacent = SQRT(Hypotenuse^2-Opposite^2) = (24.567508)
QUESTION: - What I am trying to do is this :-
- Adjust the base (& therefore the overall dimensions of the red triangle), say by reducing the value of PHI, in the MathCad worksheet.
(The dimensions of the red triangle are the height is half the base.)
- The OVERALL OBJECTIVE is to confine the Fixed lengths of Opposite, ( always in centre of red triangle), & the three legs of the Hypotenuse within a ,say smaller red triangle, ( for reduced value of PHI) but maintaining a similar configuration as outlined in figure 1 where the legs of the Hypotenuse begin & end at the top & bottom of the Opposite line respectively. As the value of PHI changes the size of the red triangle changes & then the slope of all 3 HYP/legs (which all have the same slope) increase or decrease accordingly.
I have been looking at this problem for quite some time & I am not sure if it can be done - Is my objective above possible? Please advise.
- I think it should be possible within a certain small range of values for PHI / changes in the size of the red triangle base.
If so, please could someone show this in a working MathCad worksheet, perhaps with an edited up date of mine enclosed.
Many thanks for everyone's help & attention.
Best regards - Lea...
Ps. I am version 14 of MathCAd.
Please see the enclosed MathCad worksheet & plot for an explanation of what I am trying to do.
I also enclose a PDF file with Figure 1 & Figure 2 to help explain as well.
Notes: -
#1 - Given the Fixed Hypotenuse ( =25.837) & Fixed Opposite (=8) I am trying to arrange a slope from top to bottom of the Opposite line marked in the centre of the red triangle in figure 1.
#2 - There are 3 'legs'/lines down which are HYP1, HYP2 & HYP3 which HYP1+ HYP2+ HYP3 = Hypotenuse = 25.83723
#3 - All the slopes of the legs / lines down are the same.
#4 - I have setup the current configuration for ease of explanation of what I am trying to do.
#5 - Note also that each HYP / leg meets the edge of the red triangle & the other HYP / leg start or finishes from that horizontal point.
#6 - The Combination of the vertical heights OPP1+OPP2+OPP3 = Opposite = 8
#7 - And lastly / obviously the ADJ1+ADJ2+ADJ3 = Adjacent = SQRT(Hypotenuse^2-Opposite^2) = (24.567508)
QUESTION: - What I am trying to do is this :-
- Adjust the base (& therefore the overall dimensions of the red triangle), say by reducing the value of PHI, in the MathCad worksheet.
(The dimensions of the red triangle are the height is half the base.)
- The OVERALL OBJECTIVE is to confine the Fixed lengths of Opposite, ( always in centre of red triangle), & the three legs of the Hypotenuse within a ,say smaller red triangle, ( for reduced value of PHI) but maintaining a similar configuration as outlined in figure 1 where the legs of the Hypotenuse begin & end at the top & bottom of the Opposite line respectively. As the value of PHI changes the size of the red triangle changes & then the slope of all 3 HYP/legs (which all have the same slope) increase or decrease accordingly.
I have been looking at this problem for quite some time & I am not sure if it can be done - Is my objective above possible? Please advise.
- I think it should be possible within a certain small range of values for PHI / changes in the size of the red triangle base.
If so, please could someone show this in a working MathCad worksheet, perhaps with an edited up date of mine enclosed.
Many thanks for everyone's help & attention.
Best regards - Lea...
Ps. I am version 14 of MathCAd.