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24-Ruby IV
April 14, 2020
Question

SuperMathcad

  • April 14, 2020
  • 4 replies
  • 5023 views

Fig. 1

a-sin_a.png

4 replies

24-Ruby IV
April 14, 2020

Fig. 2

sr.png

23-Emerald V
April 15, 2020

Only if one accepts that an angle *is* just the ratio of two lengths ... which hypothesis somewhat defies the observations of our eyes.

 

I prefer an alternative hypothesis in which the quantity angle is a base dimension within a system of units. This, to my eyes, makes more physical sense (how else does one capture the physical notion of rotation?).   The maths works out, ... it's just that most people won't like the 'New Units Maths' because it changes how they would do dimensional analysis.

 

Stuart

24-Ruby IV
April 15, 2020

>Only if one accepts that an angle *is* just the ratio of two lengths 

Point please second!

23-Emerald V
April 14, 2020

radians. 

 

😈

 

Stuart

(seriously)

21-Topaz II
April 15, 2020

answer to VO.jpg

16-Pearl
April 15, 2020

Just like MFra, I find the same type of expected, error-free result ONLY when I use Mathcad 15...ah the good ol' days...😎

23-Emerald V
April 16, 2020
And yet, forgotten in years since Prime was a future prospect, is how some of us were looking forward to a 'clean sheet' Mathcad that would improve Mathcad by adding new features (eg, multi-dimensional arrays and full indexing support for nested arrays, extended control programmatic control over plot formatting, programmatic worksheet animation, greater programmatic access to objects, formatted strings (eg, get a string to evaluate to a (quote-symbol-less string, with full control over fonts, styles, etc (sort of a programmed Text Box), etc (I've got a list, a very long list ...)).

I think one thing that seems to have been lost is the desire to make Mathcad much better, not just live in hope that Prime will be as good as M15 one day. Ah well.

I do wish they'd left partial application in. It would have made working with Prime *so* much easier.
24-Ruby IV
April 18, 2020

pv-2.png

21-Topaz II
April 20, 2020

Sorry but the state equation of perfect gases is: PV = nRT. So it is not clear to me what you write.

24-Ruby IV
April 20, 2020

Sorry the state equation of perfect gases is pV=T.

R is a coefficient between J/mole (a base unit of temperature) to K (one others unit of temperature).