Skip to main content
Best answer by ValeryOchkov

One compromise:

ProdFuncT.png

ELSID wrote:

Your not quite a diamond member ... YET

Yes you can do what you've done, BUT (i know, I just negated everything before the but), you can no longer use C or F as they are now "re-defined".

The definition in Mathcad of using DT works. As for your re-definition, the built-in DT values are DC=K and DF=(5/9)K and I can continue to use C or F without issues. I cannot emphasize enough that this works with papers, especially to clients and QA/QC staff who may not be as technically competent. They understand D (delta) is a change and the units after is universally accepted.

If this is a petition for PTC to eliminate the DT "unit as it currently stands, I vote to keep the status quo as my pee-wee non- PhD, diamond member, or hero of the month brain understands it clearly!

Maybe you're over thinking it Valery

I often find that educated engineers and good students usually a) know what it is default, which is widely used in engineering, c) know what is temperature and c) have ... sense of humor

In the book from NIST and ASME (see the cover below) I see only °F but not deltaF in thermal conductivity unit and °R but not deltaF as entropy or (isobaric or isohoric) heat capacity units!

http://twt.mpei.ac.ru/ochkov/WSPHB/coverEn.jpg

And second and last!

The main topic of this my messege http://communities.ptc.com/docs/DOC-3251

was not "conservative American and British people" but two temperature scale - ITS-68 and ITS-90.

PS

An old joke.
Father and son walking through Paris.
- Dad, who built the tower?
- Engineer Eiffel.
- It's like my mother - an engineer?
- No, my son, your mother is a lead engineer!

15 replies

1-Visitor
November 15, 2012

Valery,

This is a "unit" in 14 and 15 unter temperature as well. I use it all the time. It turns temperature into a liniar problem. On my Heat Transfer coefficients or equations, the "text book" formulas typically show a "change in temperature" by using the degrees F or degrees C. In my opinion, showing it as delta or change of temperature is correct. Scroll through some of my worksheets and you will see what I mean.

Example: 100C - 80C needs to equal 20C and not -253.15C. DT is a change in temperature. If we use the "standard "degree F", the result is clearly wrong.

Maybe a better request is to lump miscelaneous factors and scale units (e.g. DT, dB) into it's own category since they are not a true unit. In this case, the deltas are obviously defined as DC=K (kelvin) and DF=(5/9)K.

19-Tanzanite
November 15, 2012

I agree with El Sid. I don't see how you can eliminate the deltaT units. The fact is, T and deltaT are different things, and therefore must be represented differently.

24-Ruby IV
November 16, 2012

Richard Jackson wrote:

I agree with El Sid. I don't see how you can eliminate the deltaT units. The fact is, T and deltaT are different things, and therefore must be represented differently.

K (Kelvin) and °R (Rankin degree) but not delta°C or delta°F.

I have asked one unit expert in NIST (!!!) why in USA you use Btu/(lb °R) for entropy and Btu/(hr ft °F) for thermal conductivity. But in Europe we use kJ/(kg K) and W/(m K). Only in old old books W/(m °C).

This expert replied me that it connected with the "conservatism of the American people"