Skip to main content
J
JM_93567391-Visitor
1-Visitor
February 14, 2021
Solved

Two ranges in one equation

  • February 14, 2021
  • 1 reply
  • 2732 views

Hi,
I am having an issue where I can't get a range of values when I use two ranges in one equation:

JM_9356739_0-1613307165386.png

for hlc I am expecting a range similar to Le and v, what am I doing wrong?

Thanks!

 

Best answer by Werner_E

The auxiliary variable T should not be necessary.

Simply vectorize the whole expression on the right hand side of hlc:=... in your original sheet.

 

What you have are not called ranged but vectors.

Actually the square of a vector (v^2) is not defined from a mathematical point of view. Its NOT v*v (which would be a scalar).

Instead of throwing an error Mathcad applies implicit vectorization, squaring each element of the vector and collects the result in a new vector.

Now your formula demands Prime to multiply two vectors, Le and the newly created v^2. Prime does as demanded and gives you back the vector product, which of course is just a single scalar.
You had in mind to multiply each element of the one vector by the corresponding one of the other and this is exactly what vectorization is made for.

 

1 reply

J
JM_93567391-VisitorAuthor
1-Visitor
February 14, 2021

I found a way of doing it (typically right after I posted here), it's not the neatest solution but I used vectorization to multiply the two and put that into a single variable, then used that variable in my equation instead:

JM_9356739_0-1613308925721.png

 

W
Werner_E25-Diamond IAnswer
25-Diamond I
February 14, 2021

The auxiliary variable T should not be necessary.

Simply vectorize the whole expression on the right hand side of hlc:=... in your original sheet.

 

What you have are not called ranged but vectors.

Actually the square of a vector (v^2) is not defined from a mathematical point of view. Its NOT v*v (which would be a scalar).

Instead of throwing an error Mathcad applies implicit vectorization, squaring each element of the vector and collects the result in a new vector.

Now your formula demands Prime to multiply two vectors, Le and the newly created v^2. Prime does as demanded and gives you back the vector product, which of course is just a single scalar.
You had in mind to multiply each element of the one vector by the corresponding one of the other and this is exactly what vectorization is made for.

 

    Terms & ConditionsAccessibility statement