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J
JM_93567391-Visitor
1-Visitor
February 14, 2021
Solved

Two ranges in one equation

  • February 14, 2021
  • 1 reply
  • 2724 views

Hi,
I am having an issue where I can't get a range of values when I use two ranges in one equation:

JM_9356739_0-1613307165386.png

for hlc I am expecting a range similar to Le and v, what am I doing wrong?

Thanks!

 

Best answer by Werner_E

The auxiliary variable T should not be necessary.

Simply vectorize the whole expression on the right hand side of hlc:=... in your original sheet.

 

What you have are not called ranged but vectors.

Actually the square of a vector (v^2) is not defined from a mathematical point of view. Its NOT v*v (which would be a scalar).

Instead of throwing an error Mathcad applies implicit vectorization, squaring each element of the vector and collects the result in a new vector.

Now your formula demands Prime to multiply two vectors, Le and the newly created v^2. Prime does as demanded and gives you back the vector product, which of course is just a single scalar.
You had in mind to multiply each element of the one vector by the corresponding one of the other and this is exactly what vectorization is made for.

 

1 reply

J
JM_93567391-VisitorAuthor
1-Visitor
February 14, 2021

I found a way of doing it (typically right after I posted here), it's not the neatest solution but I used vectorization to multiply the two and put that into a single variable, then used that variable in my equation instead:

JM_9356739_0-1613308925721.png

 

W
Werner_E25-Diamond IAnswer
25-Diamond I
February 14, 2021

The auxiliary variable T should not be necessary.

Simply vectorize the whole expression on the right hand side of hlc:=... in your original sheet.

 

What you have are not called ranged but vectors.

Actually the square of a vector (v^2) is not defined from a mathematical point of view. Its NOT v*v (which would be a scalar).

Instead of throwing an error Mathcad applies implicit vectorization, squaring each element of the vector and collects the result in a new vector.

Now your formula demands Prime to multiply two vectors, Le and the newly created v^2. Prime does as demanded and gives you back the vector product, which of course is just a single scalar.
You had in mind to multiply each element of the one vector by the corresponding one of the other and this is exactly what vectorization is made for.

 

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